Question 311089
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First determine the slope of the given line.  Since the given line is in slope-intercept form, the coefficient on *[tex \Large x] is the slope of the given line.


Next, determine the slope of the line for which you want to derive an equation.  Perpendicular lines have slopes that are negative reciprocals.  That is:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  L_1\ \perp\ L_2 \ \ \Leftrightarrow\ \ m_1\ =\ -\frac{1}{m_2}\ \text{ and } m_1,\, m_2\, \neq\, 0]


Next, use the point-slope form of the equation of a line to write the equation of the desired line:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ -\ y_1\ =\ m(x\ -\ x_1) ]


where *[tex \Large \left(x_1,y_1\right)] are the coordinates of the given point and *[tex \Large m] is the negative reciprocal of the slope you determined in the first step of this solution.


The result will be an equation of the desired line.  Note any requirements as to form that your instructor/professor/teacher imposes on you and make any necessary adjustments to the point slope form to achieve the required form. 


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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