Question 311065
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First use the point-slope form of the equation of a line to derive an equation for the desired line:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ -\ y_1\ =\ m(x\ -\ x_1) ]


Where *[tex \Large \left(x_1,y_1\right)] are the coordinates of the given point and *[tex \Large m] is the given slope.


Once you have your equation, pick any value you like for *[tex \Large x] except 0.  That's because the point you were given has 0 as an *[tex \Large x] coordinate and picking 0 won't tell you anything new.  Substitute this value into the equation and do the arithmetic required to determine the value of *[tex \Large y] that results.  The ordered pair consisting of the *[tex \Large x] value you chose and the *[tex \Large y] value that resulted from that choice is a point on the line.


If you were given a series of choices that you just didn't bother to share, make your selection for *[tex \Large x] be one of the *[tex \Large x] coordinates given.  Keep checking until you find one of them that results in the listed *[tex \Large y] coordinate.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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