Question 311061
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Take the square root of both sides, remembering to consider both the positive and negative roots:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \sqrt{16(x\ +\ 3)^2}\ =\ \pm\sqrt{169}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \sqrt{16}\cdot\sqrt{(x\ +\ 3)^2}\ =\ \pm\sqrt{169}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 4(x\ +\ 3)\ =\ \pm 13]


You should be able to finish from here.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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