Question 311025
The vertex form of a parabola is,
{{{y=a(x-h)^2+k}}}
where (h,k) is the vertex.
{{{y=a(x-4)^2+2}}}
Use the point to determine {{{a}}}.
{{{-73=a(-1-4)^2+2}}}
{{{-75=25a}}}
{{{a=-3}}}
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{{{highlight_green(y=-3(x-4)^2+2)}}}
{{{ drawing( 300, 300, -3, 5, -90,10,grid(1),circle(-1,-73,.25), graph( 300, 300, -3, 5, -90, 10, -3(x-4)^2+2))}}}