Question 310889
Is this your equation?
{{{(4/9)w^2 + 1 = (5/3)w}}}
Multiply by 9 to remove all denominators,
{{{4w^2 + 9 = 15w}}}
{{{4w^2-15w+9=0}}}
Factor the quadratic
{{{(4w-3)(w-3)=0}}}
Two solutions:
{{{4w-3=0}}}
{{{4w=3}}}
{{{highlight_green( w=3/4)}}}
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{{{w-3=0}}}
{{{highlight_green( w=3 )}}}