Question 310939
Given,
A rectangle has length ( x + 11) in width 2x in 
Its perimeter = 2[x+11+2x]=6x+22
Given,
the perimeter of the rectangle is at least 47 inches and at most 52 inches 
     47< 6x+22< 52
     47-22< 6x< 52-22
     25< 6x< 30
     25/6< x < 30/6
     25/6<x<5
So the maximum value of x is 5