Question 310746
{{{N}}}, {{{N+2}}}, {{{N+4}}}, {{{N+6}}} are the odd integers.
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{{{N(N+2)=(N+4)(N+6)-112}}}
{{{N^2+2N=N^2+6N+4N+24-112}}}
{{{2N=10N-88}}}
{{{-8N=-88}}}
{{{N=11}}}
11,13,15,17 are the integers.