Question 310641
find the radius r and the center (h,k) of the following circle 
3(x-3)^2 + 3y^2 = 75
.
Circle equation:
{{{ (x-h)^2 + (y-k)^2 = r^2 }}}
where
(h,k) is the center
r is the radius
.
Starting with what was given:
{{{ 3(x-3)^2 + 3y^2 = 75 }}}
Dividing both sides by 3:
{{{ (x-3)^2 + y^2 = 75/3 }}}
{{{ (x-3)^2 + (y-0)^2 = 25 }}}
{{{ (x-3)^2 + (y-0)^2 = 5^2 }}}
.
center is at (3,0)
radius is 5