Question 36233
x^2 - 2/3x = 0
=> x^2 - 2*1/3*x + (1/3)^2 = 0 + (1/3)^2
=> (x-1/3)^2 = (1/3)^2
=> (x-1/3) = 1/3 or (x-1/3) = -1/3
=> x = 2/3 or x = 0