Question 310375
Let {{{u=x^(1/5)}}}, then {{{u^2=x^(2/5)}}}.
{{{u^2-u-12=0}}}
{{{(u-4)(u+3)=0}}}
Two solution:
{{{u-4=0}}}
{{{u=4}}}
{{{x^(1/5)=4}}}
{{{x=4^5}}}
{{{highlight( x=1024)}}}
.
.
.
{{{u+3=0}}}
{{{u=-3}}}
{{{x^(1/5)=-3}}}
{{{x=(-3)^5}}}
{{{highlight( x=-243)}}}