Question 310346
It's not an equation. For it to be an equation, there would have
to be an = sign somewhere.
It's called an algebraic expression
{{{(x^2 - 9)/(2x + 6)}}}
First, factor out {{{2}}} from the denominator
{{{(x^2 - 9)/(2*(x + 3))}}}
You can rewrite this as:
{{{(1/2)*((x^2 - 9)/(x + 3))}}}
Now factor the numerator
{{{(1/2)*((x + 3)*(x - 3)/(x + 3))}}}
{{{(1/2)*(x - 3)}}}
{{{(x-3)/2}}} answer
------------------
I can check by choosing any number for {{{x}}} like
{{{x = 11}}}
{{{(x^2 - 9)/(2x + 6)}}}
{{{(11^2 - 9)/(2*11 + 6)}}}
{{{(121 - 9)/(22 + 6)}}}
{{{112/28}}}
{{{4}}}
and for the answer:
{{{(x - 3)/2}}}
{{{(11 - 3)/2}}}
{{{8/2}}}
{{{4}}}
OK