Question 310338
s  is the sum of the first 100 consecutive positive even integers , and t is the sum of the first 100 consecutive positive integers . s is what percent greater 
than  t ?

a  100%   b  50%   c  10%  d  2%   e  1%

1/2 * n(n+1) = sum all numbers from 1 to n
n^2 = sum 1st n odd numbers
n(n+1) = sum 1st n even numbers

s/t = 100(101)/(1/2 * 100 * 101) = 10100/(50 * 101) = 10100/5050 = 2

answer is a) 100%