Question 310306
Chuck and Dana agree to meet in chicago for the weekend.
Chuck travels 114 miles in the same time that Dana travels 96 miles. If Chuck's rate of travel is 6 mph more than Dana's, then at what rate does chuck travel?
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Chuck distance (x+6)t = 114
Dana distance xt = 96
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xt+6t = 114
xt = 96
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Substitute and solve for "t":
96 + 6t = 114
6t = 18
t = 3 hrs
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Chuck rate: 114/(3) = 38 mph
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Cheers,
Stan H.
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