Question 310072
y = x2+4x+3 
The parabola graph puts it as: x= -1, -3. 
The equation didn't have negative numbers in it in the first place. So why does the graph make them negatives?
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{{{y = x^2+4x+3 }}}
Find where y = 0:
{{{x^2+4x+3 = 0}}}
(x+3)*(x+1) = 0
For the product to be 0, either x+3 = 0 or x+1 = 0
x+3 = 0
x = -3
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x+1 = 0
x = -1