Question 310022
1/3log[2](x + 6) = log[8](3x). Solve the equation
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log2(x+6)^(1/3) = log8(3x)
log2(x+6)^(1/3) = log2(3x)/log2(8)
log2(x+6)^(1/3) = (1/3)log2(3x)
log2(x+6)^(1/3) = log2(3x)^(1/3)
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x+6 = 3x
2x = 6
x = 3
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Cheers,
Stan H.