Question 309980
{{{3(x+4)=2-3(x+1)}}}
{{{3(x+4)+3(x+1)=2}}}
{{{3x+12+3x+3=2}}}
{{{6x+15=2}}}
{{{6x=-13}}}
{{{x=-13/6}}}
Then substitute into the inequality,
{{{x > y + 3x  }}}
{{{y<-2x}}}
{{{y<-2(-13/6)}}}
{{{y<13/3}}}
{{{13/3=4+1/3}}}
4 is the largest integral value of y.