Question 309950
I need help finding the real solution to this equation.

(y - 2/3)^2 = 4/9


{{{sqrt((y - (2)/3)^2)}}} = +-{{{sqrt(4/9)}}} ---- Take square root of each side

{{{y - 2/3)}}} = +-{{{2/3}}}


{{{y = (2/3) + (2/3)}}} or {{{y = -(2/3) + (2/3)}}}


{{{highlight_green(y = (4/3))}}} or {{{highlight_green(y = 0)}}}