Question 309849
a) First, factor:
{{{N(t) = -3t^3+23t^2+8t}}} Factor a -t.
{{{N(t) = -t(3t^2-23t-8)}}} Now, factor the trinomial.
{{{N(t) = -t(3t+1)(t-8)}}}
{{{N(3) = -3(3*3+1)(3-8)}}}
{{{N(3) = -3(10)(-5)}}}
{{{N(3) = -30(-5)}}}
{{{highlight(N(3) = 150)}}}