Question 309817
{{{x= (5y-3)/(y+2)}}}
<pre><b>
Put a 1 under the x

{{{x/1= (5y-3)/(y+2)}}}

Cross-multiply:

{{{x(y+2)=1(5y-3)}}}

Distribute:

{{{xy+2x=5y-3}}}

Isolate terms which contain y by adding {{{-2x-5y}}} to both sides:

{{{xy-5y=-2x-3}}}

Factor out y on the left:

{{{y(x-5)=-2x-3}}}

Divide both sides by {{{(x-5)}}}

{{{(y(x-5))/((x-5))=(-2x-3)/((x-5))}}}

Cancel:

{{{(y*cross((x-5)))/(cross((x-5)))=(-2x-3)/(x-5)}}}

{{{y=(-2x-3)/(x-5)}}}

Edwin</pre>