Question 309598
IF THE VERTICLE LINE IS ONE OF THE SIDES & IT'S A RIGHT TRIANGLE THEN:
10^2+24^2=C^2
100+576=C^2
C^2=676
C=SQRT676
C=26 m.
iF THE VERTICLE ANGLE IS THE MIDDLE HEIGHT OF THE TRIANGLE THEN:
5^2+24^2=C^2
25+576=C^2
C^2=601
C=SQRT601
C=24.5m. 
ALL OTHER VERTICLE LINES WILL RESULT IN THE THIRD SIDE BEING BETWEEN 
24.5M. & 26 m.