Question 309501
How do I solve this equation and check for extraneous solutions? 
3 sqrt(w + 1) = 6
----
sqrt(w+1) = 2
w+1 = 4
w = 3
-----
Checking:
3*sqrt(4) = 6
3*2 = 6
-----
Solution: w = 3
==================
Cheers,
Stan H.