<PRE><B>Question 309440</B>
a frog leaps off the ground at 2 feet per second; how many seconds does it take the frog to land
.
Your equation:
h(t) = (1/2)32t^2 + 2t
.
Set h(t) to zero and solve for t:
0 = -(1/2)32t^2 + 2t
0 = -16t^2 + 2t
0 = -8t^2 + t
0 = t(-8t + 1)
.
t = {0, 1/8}
Toss out the zero solution (this is when the frog just started the leap) leaving you:
t = 1/8 second
or
t = 0.125 seconds
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