Question 309381
Solve for x:
{{{Log(7)+Log(x) = 2}}} First, apply the "product rule" for logarithms: {{{Log(M)+Log(N) = Log(M*N)}}}
{{{Log(7*x) = 2}}} Now write this in exponential form: {{{Log[b](x) = y}}}--->{{{b^y = x}}}
{{{10^2 = 7*x}}} Divide both sides by 7.
{{{10^2/7 = x}}} S0...
{{{highlight(x = 100/7)}}}