Question 309336
Mean, {{{mu}}}
{{{mu = sum(x*P(x),1,3)=1*(0.1)+2*(0.6)+3*(0.3)=0.1+1.2+0.9=2.2}}}
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Standard Deviation, {{{sigma}}}
{{{sigma^2= sum((x-mu)^2*P(x),1,3)=(1-2.2)^2*(0.1)+(2-2.2)^2*(0.6)+(3-2.2)^2*(0.3)=0.144+0.024+0.192=0.36}}}
{{{sigma=0.6}}}