Question 36129
We can use substitution of y to say x^2-3=2x+1.  So we have a quadratic equation to solve.  We can write this as x^2-2x-4=0, and use the quadratic formula to get {{{x = (2 +- sqrt( 4+16 ))/(2) }}}, so {{{x = (2 +- sqrt( 20 ))/(2) }}}, so x=1+sqrt5, 1-sqrt5