Question 36114
2 ways:
If the inequality is of the form y>mx+b, it is the area above the line, if it is y(less than)mx+b, it is the area below.  A method that will work regardless of the form of the inequality is to test points above or below.  For example if I have 9x+3y>6, I  draw the (dotted) line with slope -3 and y-intercept 2.  I then test any point not on the line, so (0,0) is usually a nice simple choice.  9(0)+3(0)=0, which is not >6, so (0,0) is not in the shaded region.  So the area above the line is shaded.
Note, if we wrote this inequality in slope-intercept form, we'd have y>-3x+2, so also by our first method the area above the line is shaded.