Question 309238
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ +\ \frac{5}{6}\ =\ 3\frac{1}{2}]


Step 1:  Change the mixed fraction to an improper fraction.  2 times 3 plus 1 = 7 so:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ +\ \frac{5}{6}\ =\ \frac{7}{2}]


Step 2:  Add *[tex \Large -\frac{5}{6}] to both sides


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ =\ -\frac{5}{6}\ +\ \frac{7}{2}]


Step 3:  Find and apply the LCD.  LCD for 2 and 6 is 6.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ =\ -\frac{5}{6}\ +\ \frac{7}{2}\left(\frac{3}{3}\right)]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ =\ -\frac{5}{6}\ +\ \frac{21}{6}]


Step 4: Add the fractions


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ =\ \frac{16}{6}]


Step 5: Reduce the fraction to lowest terms


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ =\ \frac{8}{3}]


Stop here unless you have instructions to either provide a decimal approximation:  *[tex \Large 2.667] or a mixed number: 3 goes into 8 two times remainder 2, so *[tex \Large 2\frac{2}{3}]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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