Question 309199
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Since the cars are travelling toward each other, the exact same time would elapse if one of the cars wasn't moving at all and the other car was travelling the sum of the two speeds.


Distance equals rate times time, so rate is equal to distance divided by time.  6 minutes is 0.1 hour.  So 36 minutes 6 times 6 minutes so it is 6 times 0.1 hour is 0.6 hour.  So 1 hour 36 minutes is 1.6 hours. 


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{192}{1.6}\ =\ 120]


So the sum of the two cars speeds is 120 miles per hour.


Let *[tex \Large x] represent the slower car's speed and then *[tex \Large x\ +\ 10] represents the faster car's speed.  And we now know that:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ +\ x\ +\ 10\ =\ 120]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 2x\ =\ 110]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ =\ 55]


The slower car goes 55 mph, and the faster one goes 65.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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