Question 309203
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ -9x\ +\ \frac{5}{7}\ =\ \frac{7}{9}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ -9x\ =\ \frac{7}{9}\ -\ \frac{5}{7}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ -9x\ =\ \frac{49}{63}\ -\ \frac{45}{63}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ -9x\ =\ \frac{4}{63}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \left(-\frac{1}{9}\right)(-9x)\ =\ \left(-\frac{1}{9}\right)\frac{4}{63}]  And here is your problem.  You multiplied by 9 instead of dividing by -9.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ =\ -\frac{4}{567}]


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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{2}{5}(10x\ -\ 3)\ -\ x\ =\ \frac{9}{5}]


You said *[tex \LARGE 10x\ -\ 3\ = 7x] BUZZ!!! Sorry, that is incorrect.  You can't combine unlike terms.  10x has an x, 3 doesn't.  That makes the terms unlike.  Game over, but thank you for playing.


First, distribute the *[tex \LARGE \frac{2}{5}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ (4x\ -\ \frac{6}{5})\ -\ x\ =\ \frac{9}{5}]


Then collect terms:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 3x\ =\ \frac{9}{5}\ +\ \frac{6}{5}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \left(\frac{1}{3}\right)3x\ =\ \left(\frac{1}{3}\right)\frac{15}{5}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ =\ \frac{5}{5}\ =\ 1]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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