Question 309180
A construction company spent 26 hours on two jobs.
 One job took 5 more the twice the number of hours of the other.
 How long did the larger job take? 
:
Let x = time for larger job
Let y = time for the other job
:
"A construction company spent 26 hours on two jobs."
x + y = 26
y = (26-x); this form for substitution
:
"One job took 5 more the twice the number of hours of the other."
x = 2y + 5
:
 How long did the larger job take?
Replace y with (26-x) in the above equation
x = 2(26-x) + 5
x = 52 - 2x + 5
x + 2x = 52 + 5
3x = 57
x = {{{57/3}}}
x = 19 hrs
:
:
Check solution; y = 26-19 = 7 hrs
"One job took 5 more the twice the number of hours of the other." 
19 = 2(7) + 5