Question 309164
Put the equation in standard ellipse form,
{{{(x+2)^2+4(y-5)^2=36}}}
{{{(x+2)^2/36+4(y-5)^2/36=1}}}
{{{(x+2)^2/6^2+(y-5)^2/3^2=1}}}
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a=6
b=3
Center=(-2,5)
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 {{{ drawing( 300, 300, -10, 4, -2, 12,  grid(1),circle(-2,5,.3),circle(4,5,.3),circle(-8,5,.3),circle(-2,8,.3),circle(-2,2,.3),graph( 300, 300, -10, 4, -2, 12, 
5+sqrt((36-(x+2)^2)/4), 5-sqrt((36-(x+2)^2)/4))) }}}