Question 667
This equation doesn't factor, so the quadratic formula is probably the best choice for how to solve it.
The quadratic formula is:
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 
This formula assumes you know that the equation needs to be in 
the form of {{{ax^2 + bx + c = 0}}}.
For your equation:
a = 2
b = -7
c = -3

So, when you plug in the a, b and c, you get:
{{{n = (-2 +- sqrt((-7)^2-4*2*(-3)))/(2*2)}}}

When you simplify the information under the square root and in the denominator, you get:
{{{n = (-2 +- sqrt(49+24))/(4)}}}
Then:
{{{n = (-2 +- sqrt(75))/(4)}}}
Then simplify the square root. {{{sqrt(75)=sqrt(25)*sqrt(3)=5 sqrt(3)}}}
This leaves you with:
{{{n = (-2 +- 5 sqrt(3))/(4)}}}
This can be your final two answers, unless it needs to be in decimal form and that requires a calculator or square root table.