Question 308970
Solve 2log4- log3 +2 logx-4 = 0
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log(16) - log(3) + log(x-4)^2 = 0
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log[(16/3)(x-4)^2] = 0
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(16/3)(x-4)^2 = 10^0
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(16/3)(x-4)^2 = 1
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(x-4)^2 = 3/16
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x-4 = +-sqrt(3)/4
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x = 4 +- (1/4)sqrt(3)
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Cheers,
Stan H.
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A) 12.3308
B) 43.3013
C) 86.6025
D) 1875