Question 308937
y= x^2 + 10x + 16
=(x^2+10x+25)-25+16 completing the square
=(x+5)^2-9 the standard form
Since y=a(x-h)^2+k is the standard form then a=1, h=-5, k=-9
The vertex is (h,k)=(-5,-9)
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Ed
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{{{graph(500,500,-10,10,-10,10,x^2+10x+16)}}}