Question 308795
(x-4)^2+(y-0)^2 =13 but now I have to determine where the circle intersects the x-axis using a system of equations. 
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Let y = 0; then solve for "x":
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(x-4)^2 = 13
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x-4 = +-sqrt(13)
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x = 4+sqrt(13) or x = 4-sqrt(13)
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Cheers,
Stan H.