Question 36060
If I understand the problem correctly;
{{{(x-1)(x^2+5x+1)/(7x-7)(x^2+5x+1)}}}
factor out the 7 in the denominator;
{{{(x-1)(x^2+5x+1)/7(x-1)(x^2+5x+1)}}}
cancel out (x-1)and {{{x^2+5x+1}}}
you are left with;
{{{1/7}}}
Hope you understand
=)