Question 308677
How do I multiply this fraction? 
[ (x2 – y2) / (x2 + xy) ][ (3x2 + 6xy ) / (x2 + xy – 2y2) ] 
[ (x^2 – y^2) / (x^2 + xy) ][ (3x^2 + 6xy ) / (x^2 + xy – 2y^2) ]
{{{ ((x^2 - y^2)/(x^2 + xy))((3x^2 + 6xy)/(x^2 + xy - 2y^2)) }}}
{{{ (((x + y)(x - y))/(x(x + y)))((3x(x + 2y))/((x + 2y)(x - y))) }}}
{{{ ((x - y)/x)(3x/(x - y)) }}}
{{{ (3x(x-y))/(x(x-y)) }}}
{{{ 3x/x }}}
{{{ 3 }}}
with 2 fractions you multiply straight across and then simplify if possible, 
for example 2/3 * 3/5 = 6/15 = 2/5
in this problem's case I simplified the numerators and denominators and factored out the like terms, then I multiplied and simplified