<PRE><B>Question 308569</B>
 Lisa has nine rings in her jewelry box. Five are gold and four are silver. If she randomly selects 3 rings to wear to a party, find each probability:
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P(2 silver or 2 gold) = P(2 silver) + P(2 gold) = 5C2/9C2 + 4C2/9C2 
= [10+6]/36 = 4/9
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P(at least 2 gold) = P(2 gold) + P(3 gold) = 5C2/9C2 + 5C3/9C2 
= [10+10]/36 = 5/9
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Cheers,
Stan H. 
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