Question 308520
I am trying to solve the following: x^2 -4x -3 = 0. I can get as far as 4 plus or minus the sqrt of 28 over 2. I don't understand why this becomes 2 plus or minus the sqrt of 7. It seems to me that it should be 2 plus or minus the sqrt of 14. 
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Quadratic Formula: 
x = [-b +- sqrt(b^2-4ac)]/(2a)
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x = [4 +- sqrt(4^2 - 4*1*-3)]/(2*1)
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x = [4 +- sqrt(28)]/2
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x = [4 +- 2sqrt(7)]/2
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x = [2+sqrt(7)] or x = [2-sqrt(7)]
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Cheers,
Stan H.
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