Question 308022
The maximum or minimum of a quadratic function occurs when x=-b/2a.

In this case, a=3, b=12, so x=-12/6=-2.


f(-2)=3(-2)^2+12(-2)+8
f(-2)=3*4+(-24)+8
f(-2)=12+(-16)=-4 = minimum value of f(x).


Are graphing calculators allowed???


Dr. Robert J. Rapalje, Retired