Question 307925
 x^2+y^2-8x-16y+44=0 
i need to find the center and radius of this circle.
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Rearrange it into "standard form", (x-h)^2 + (y-k)^2 = r^2
{{{x^2 - 8x + y^2 -16y = -44}}}
Complete both squares for x and y
{{{x^2 - 8x + 16 + y^2 - 16y + 64 = -44 + 16 + 64 = 36}}}
{{{(x-4)^2 + (y-8)^2 = 6^2}}}
---> center at (h,k) = (4,8)
radius = 6