Question 307804
Find the equation of the line passing through (-1, -3) and perpendicular to y = -2x + 3.

y= -2x +3

slope = -2 

slope of perpendicular line = +1/2

x1,y1 (-1, -3)

equation of line passing through a point x1 y1
y-y1 = m(x-x1)

y-(-3)= 1/2 ( x-(-1))

y+3 = 1/2 (x+1)

2y+6 =x+1
2y= x-5
y= 1/2 x -5/2 is the perpendicular line