Question 35957
LET X= THE NUMBER OF DIMES THEN THE NUMBER OF NICKLES (X-1) AND THE NUMBER OF QUARTERS (X+1) THUS 10X+5(N-1)+25(N+1)=500 OR 10X+5N-5+25N+25=500 OR
40X=480 OR X=480/40 OR X=12 THUS THE NUMBER OF DIMES IS 12 OR $1.20 THE NUMBER OF NICKLES ID 11 OR 5*11=$.55 & THE NUMBER OF QUARTERS IS 25*13=$3.25
$1.20+$.55+$3.25=$5.00