Question 307640
Let x = a number
Let y = a second number
:
Write an equation for each statement, then simplify the equation:
:
"The sum of two numbers is six less than twice the first number."
x + y = 2x - 6
y = 2x - x - 6
y = (x - 6)
:
" When the second number is subtracted from the first, the difference is ten less than four times the second number."
x - y = 4y - 10
x = 4y + y - 10
x = 5y - 10
replace y with (x-6), find x
x = 5(x-6) - 10
x = 5x - 30 - 10
x - 5x = -40
-4x = -40
x = +10
find y
y = 10 - 6
y = 4 is the 2nd number
:
Check solution in the 1st statement:
"The sum of two numbers is six less than twice the first number."
10 + 4 = 2(10) - 6