Question 307584
Solve by substitution:
{{{6x-y = 10}}}
{{{y = (-3/4)x -1}}} Substitute this for y in the first equation.
{{{6x-(-(3/4)x-1) = 10}}} Simplify the left side.
{{{6x+(3/4)x+1 = 10}}} Multiply through by 4 to clear the fraction.
{{{24x+3x+4 = 40}}} Combine the x's.
{{{27x+4 = 40}}} Subtract 4 from both sides.
{{{27x = 36}}} Divide both sides by 27.
{{{highlight(x = 1.3)}}} to the nearest tenth.