Question 35941
{{{7X(1-X)= 5(X-2)}}}


{{{7x -7x^2 = 5x- 10}}}


This is a quadratic equation because of the {{{x^2}}} term, so the first step must be to set it equal to zero.  To avoid a troublesome negative coefficient of {{{x^2}}}, I would move everything to the right side by adding {{{+7x^2 - 7x}}} to each side:

{{{7x - 7x^2 - 7x + 7x^2 = 5x - 10 - 7x + 7x^2}}}
{{{0 = 7x^2 - 2x - 10 }}}


Hopefully this will factor:   {{{0= (7x_____)(x_____) }}}


However, it does NOT.  So let's invoke a quadratic equation solver from algebra.com.
*[invoke solve_quadratic_equation 7, -2, -10]


I think the answer you should get from this is reduces to {{{ (1 +- sqrt(71))/7}}}.


R^2 at SCC