Question 307523
Solve by factoring:
{{{3x^2-3x = 18}}} First subtract 18 from both sides.
{{{3x^2-3x-18 = 0}}} Now factor a 3.
{{{3(x^2-x-6) = 0}}} which means that:
{{{x^2-x-6 = 0}}} Factor this trinomial.
{{{(x-3)(x+2) = 0}}} Apply the zero product rule: If {{{a*b = 0}}} then either {{{a = 0}}} or {{{b = 0}}} or both.
{{{x-3 = 0}}} or {{{x+2 = 0}}} so that...
{{{highlight(x = 3)}}} or {{{highlight(x = -2)}}}