Question 307279
{{{((x^2+3x)/(x^2-6x+8))*((x^2-7x+12)/(x^2-9))}}}
Start by factoring the numerators and the denominators of both fractions.
{{{(x*cross((x+3))/(x-2)cross((x-4)))*((cross(x-3))cross((x-4))/cross((x+3))cross((x-3)))}}} Now cancel all of the common factors and you are left with:
{{{highlight(x/(x-2))}}}