Question 35897
If the generating polynomial has three zeros, then it must be a third-degree polynomial, right?
Remember how you find the zeros? You set the factors equal to zero and solve for the variable.
Ex. (x-6i) is a factor, set x-6i = 0, so x = 6i
If 6i is a zero, then x-6i is a factor. 
If -6i is a zero, then x+6i is a factor.
If -1 is a zero, then x+1 is a factor.

Now to get the polynomial back, you need to multiply the three factors.
{{{(x+6i)(x-6i)(x+1) = (x^2-36i^2)(x+1)}}} = {{{(x^2+36)(x+1)}}} = {{{x^3+x^2+36x+36}}}