Question 307174
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ (a\ +\ b)^2\ =\ 25]


So


Eq. 1:  *[tex \LARGE \ \ \ \ \ \ \ \ \ \ a^2\ +\ 2ab\ +\ b^2\ =\ 25]


Then


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ (a\ -\ b)^2\ =\ 45]


So


Eq. 2:  *[tex \LARGE \ \ \ \ \ \ \ \ \ \ a^2\ -\ 2ab\ +\ b^2\ =\ 45]


Add Eq. 1 to Eq. 2:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 2a^2\ +\ 2ab\ -\ 2ab\ +\ 2b^2\ =\ 70]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ a^2\ +\ b^2\ =\ 35]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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